Visual Optics Test 2025 – 400 Free Practice Questions to Pass the Exam

To determine the amount of accommodation required for an uncorrected 2.5 D hyperope to read at a distance of 33.33 cm, it's important to understand the relationship between the eye's refractive status and the working distance.

Hyperopia, or farsightedness, is a condition where distant objects can be seen clearly, but close objects require additional effort from the eye to focus. In the case of a hyperope with a +2.5 D prescription, this means that to see near objects clearly, the individual has to exert accommodation.

The working distance of 33.33 cm corresponds to a near visual task. First, we can convert this distance into diopters using the formula for optical power:

\[

\text{Diopters (D)} = \frac{1}{\text{Distance in meters}} = \frac{1}{0.3333} \approx 3.0 D

\]

Thus, an object at 33.33 cm requires about 3.0 D of accommodation.

Since the individual is a +2.5 D hyperope, they can only focus at their uncorrected vision to +2.5 D without accommodation. Therefore, to achieve clear vision at this working